Q3 of 23 Page 266

In the figure PR and QS are two diameters. Is PQ = RS?

Considering a circle, where PR and QS being a diameter.


Let center of circle be O.


In triangles POQ and SOR


PO = OR (Radius of circle)


OS = OQ (Radius of circle)


Angle POQ = Angle SOR (Vertically opposite angles are always


equal)


Hence triangle POQ is congruent to triangle SOR (By Side Angle Side


Axiom)


PQ = RS (By C.P.C.T.C)


Hence, proved.


More from this chapter

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1

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In the figure, PQ = RS and ∠ORS = 48°. Find ∠OPQ and ∠ROS.

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(i) In ∆ ABC, AB = 6cm, BC = 7cm and ∠A = 60°


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(iii) In ∆ XYZ, XY = 4.8cm, ∠X = 60° and ∠Y = 70°

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