In the given figure ‘O’ is the centre of the circle and AB, CD are equal chords. If ∠AOB = 70°. Find the angles of the ∆OCD.

We know “Angles subtended by equal chords at the center of a circle are equal”.
∠DOC = ∠AOB = 70![]()
In
OCD,
∠OCD + ∠ODC + ∠DOC = 180![]()
x + x + 70
= 180![]()
700 + 2x = 180![]()
2x = 180
-70![]()
2x = 110![]()
x = ![]()
x = 55![]()
∠OCD = ∠ODC = 55![]()
Couldn't generate an explanation.
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