Find the values of x and y in the figures given below.
i. 
ii. 
iii. 
(i) We know “Sum of all angles of a triangle is 180
”.
x + y + 30
= 180![]()
Since it is an isosceles triangle, x = y.
x + x + 30
= 180![]()
⇒ 2x + 30
= 180![]()
⇒ 2x = 180
-30![]()
⇒ 2x = 150![]()
⇒ x = ![]()
⇒ x = 75![]()
x = y = 75![]()
(ii) We know that “Angles on the opposite sides in the cyclic quadrilateral are supplementary”.
x + 110
= 180![]()
⇒ x = 180
-110![]()
⇒ x = 70![]()
y + 85
= 180![]()
⇒ y = 180
-85![]()
⇒ y = 95![]()
(iii) Given, x = 90°
x + y + 50
= 180![]()
⇒ 90
+ y + 50
= 180![]()
⇒ y + 140
= 180![]()
⇒ y = 180
-140![]()
⇒ y = 40![]()
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