If
, find (A + B)C and AC + BCIs (A + B)C = AC + BC ?
⇒ A =
, B =
and C = ![]()
⇒ A + B = ![]()
= ![]()
⇒ A + B = ![]()
⇒ (A + B)C = ![]()
= ![]()
= ![]()
⇒ AC = ![]()
= ![]()
= ![]()
⇒ BC = ![]()
= ![]()
= ![]()
⇒ AC + BC = ![]()
= ![]()
⇒ Thus (A + B)C = AC + BC is true
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