Find the quotient the and remainder of the following division.

(2x² – 3x – 14) ÷ (x + 2)

(2x² – 3x – 14) ÷ (x + 2)

We see that the equation is already arranged in descending order.

Now we need to divide (2x² – 3x – 14) by (x + 2).

Now we need to find out by how much should we multiple “x” to get a value as much as 2x².

To get x², we need to multiply x×x.

Therefore, we need to multiply with 2x × (x + 2) and we get (2x² + 4x) now subtract (2x² + 4x) from 2x² – 3x – 14 so we get –7x.

Now we carry 14 along with –7x, as shown below

So, in same way we have keep dividing till we get rid of x as shown below.

here (x + 2) × (– 7)

= – 7x – 14

Therefore, we got the quotient = 2x – 7 and

Remainder = 0