Q3 of 47 Page 80

Using factor theorem show that (x – 1) is a factor of 4x3 – 6x2 + 9x – 7.

f(x) = 4x3 – 6x2 + 9x – 7

By factor theorem,


(x – 1) = 0 ; x = 1


Since, (x – 1) is a factor of f(x)


Therefore, f(1) = 0


f(1) = 4(1)3 – 6(1)2 + 9(1) – 7 = 4 – 6 + 9 – 7 = 13 – 13 = 0


∴(x – 1) is a factor of f(x)


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