Let l1 || l2 and m1 is a transversal. If ∠F = 65°, find the measure of each of the remaining angles.

Given: ∠F = 65°
∠B = ∠F = 65° {Corresponding angle}
∠H = ∠F = 65° {vertically opposite angle}
∠D = ∠B = 65° {vertically opposite angle}
Also, ∠C + ∠F = 180° {co-interior angles are supplementary}
⇒ ∠C = 180° - 65°
⇒ ∠C = 115°
∠E = ∠C = 115° {Alternate interior angle}
∠G = ∠C = 115° {Corresponding angle}
∠A = ∠G = 115° {Alternate exterior angle}
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