In the given figure, OP bisect ∠ BOC and OQ bisect ∠ AOC. Then ∠ POQ is equal to

Suppose that
BOC = 2x and ∠ AOC = 2y
Now, by question; OP and OQ is the bisect or of ∠ BOC and ∠ AOC respectively.
⇒ ![]()
Similarly,
![]()
Now,
∠ POQ = ∠ POC + ∠ COQ = x + y
So, we have to find ∠ POQ i.e.x + y Now, ∠ BOC + ∠ AOC = 180
⇒ 2x + 2y = 180
⇒ 2(x + y) = 180
⇒ x + y = 180/2
⇒ x + y = 90°
Hence, ∠ POQ = 90°.
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