Q3 of 18 Page 70

In each picture below, the explanation of the green part is given. Calculate in each, the probability of a dot put without looking to be within the green part.

Circle exactly fitting inside a square.


The figure is shown below:



Let the side of square be 2x


Also, RS = 2x


RS is also the diameter of the circle.


Radius


Now,


Area of square = 4 × side


= 4 × 2x


= 8x


Area of green region(circle) = πr2


= π x2


Probability of dot is putted in the green part







= 0.40x (approx.)


More from this chapter

All 18 →
1

In each picture below, the explanation of the green part is given. Calculate in each, the probability of a dot put without looking to be within the green part.

A square got by joining the midpoints of a bigger square.


 2

In each picture below, the explanation of the green part is given. Calculate in each, the probability of a dot put without looking to be within the green part.

A square with all vertices on a circle.


 4

In each picture below, the explanation of the green part is given. Calculate in each, the probability of a dot put without looking to be within the green part.

A triangle got by joining alternate vertices of a regular hexagon.


 5

In each picture below, the explanation of the green part is given. Calculate in each, the probability of a dot put without looking to be within the green part.

A regular hexagon formed by two overlapping equilateral triangles.