From all two-digit numbers with either digit 1, 2, or 3 one number is chosen.
i) What is the probability of both digits being the same?
ii) What is the probability of the sum of the digits being 4?
Sample space:
11, 12, 13
21, 22, 23
31, 32, 33
i Total number of numbers formed = 9
Total number of numbers having same digit = 3
Probability of both digits being the same
![]()
![]()
= 0.33
ii Total number of numbers formed = 9
Total number of numbers sum being 4 = 3
Probability of both digits being the same
![]()
![]()
= 0.33
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.