A triangle is to be drawn with one side 8 centimetres and an angle on it 40°. What is the minimum length of the side opposite this angle?
We know that perpendicular length drawn between two lines is the smallest length.
Let AB = 8 cm and ∠ BAX = 40°

From B draw perpendicular on AX say BC.
In Δ ABC,
BC = AB × sin 40°
(From table, sin 40° = 0.64)
⇒ BC = 8 × 0.64 cm
⇒ BC = 5.12 cm
The minimum length of the side opposite to angle 40° is 5.12 cm.
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