One angle of a rhombus is 50° and one diagonal is 5 centimetres. What is the area?
The rhombus ABCD is as shown in the figure shown below,

where,
DB = 5 cm
∠ADC = 50°
We know that,
Diagonals of a rhombus are perpendicular bisector to each other.
Also, diagonals bisect the corner angles of rhombus
So,
∠ODC = 25° [∵ DB bisects ∠D]
OD = 2.5 cm [∵ AC bisects BD]
Now OC is given by,
OC = OD × tan25°
OC = 2.5 × 0.466
OC = 1.166 cm
Also, AC = 2 × OC [∵ BD bisects AC]
AC = 2 × 1.166
AC = 2.332 cm
We know, Area of rhombus = ![]()
Area ![]()
Area ![]()
Area ![]()
Couldn't generate an explanation.
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