Write two integers which are greater than – 10 but their sum is smaller than – 10.
There are number of integers that are greater than -10, namely
-9, -8, -7, -6, -5, -4, -3, -2, -1, 0, 1, 2, …
We need to do this type of question by hit and trial basis. So, take a look at the integers greater than -10.
If we add any positive integer to a positive integer, then we would get a positive integer in result, which would not be smaller than -10.
Any positive integer is greater than -10.
So, try subtracting some negative integers together. Adding -5 to -6 or -6 to -7 or such pairs would work. So,
Difference = -6 + (-7)
⇒ Difference = -6 - 7 [minus & minus = plus]
⇒ Difference = -13, which is smaller than -10 [∵ 7 is the greatest number of 6 and 7, so the sign before 7 would be taken in the result]
Similarly, there are other pair of integers satisfying the condition.
Thus, -6 and -7 are one of such integers.
Couldn't generate an explanation.
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