If * is an operation such that for integers a and b we have
a * b = a × b + (a × a + b × b)
then find (i) (– 3) * (– 5)
(ii) ( – 6) * 2
We have been given that,
a * b = a × b + (a × a + b × b) …(i)
Apply the same formula in the questions that follows:
(i). We have (-3) * (-5).
Put a = -3 and b = -5 in equation (i), we get
(-3) * (-5) = (-3) × (-5) + (-3 × -3 + -5 × -5)
⇒ (-3) * (-5) = 15 + (9 + 25)
⇒ (-3) * (-5) = 15 + 9 + 25
⇒ (-3) * (-5) = 49
Thus, the answer is 49.
(ii). We have (-6) * 2.
Put a = -6 and b = 2 in equation (i), we get
(-6) * 2 = (-6) × 2 + (-6 × -6 + 2 × 2)
⇒ (-6) * 2 = -12 + (36 + 4)
⇒ (-6) * 2 = -12 + 40
⇒ (-6) * 2 = 28
Thus, the answer is 28.
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