Match each of the entries in Column I with the appropriate entries in Column II:
Column I
i. 3:5
ii. 2.5
iii. 100%
iv. ![]()
vi. 12.5%
vii. SP when CP = Rs 50 and loss = 6%
viii. SP when CP = Rs 50 and profit = Rs 4
ix. Profit % when CP = Rs 40 and SP = Rs 50
x. Profit when CP = Rs 50 and SP = Rs 60
xi. Interest when principal = Rs 800,
Rate of interest = 10% per annum and period = 2 years
xii. Amount when principal = Rs 150, Rate of interest = 6% per annum and period = 1 year
Column II
A. Rs 54
B. Rs 47
C. Rs 53
D. Rs 160
E. 60%
F. 25%
G. ![]()
H. 250%
I. Rs 159
J. 
K. 20%
L. 0.125
M. 3 : 2
N. Rs 164
O. 3 : 3
i) Mathces to E
Given, ratio = 3:5
In Percentage,
× 100% = 60%
ii) Matches H
Given, 2.5
In Percentage, 2.5 × 100% = 250%
iii) Matches O
Given, 100%
⇒ Ratio = 100%:1
=
: 1
⇒ Ratio = 1:1
= 1× 3:1×3
= 3:3
iv) Matches J
Given, ![]()
In Percentage,
× 100% =
%
v) Matches G
Given,
= ![]()
For Fraction,
×
= ![]()
vi) Matches L
Given, 12.5%
For fraction,
= ![]()
For decimal,
= 0.125
vii) Matches B
Given, CP = 50, Loss% = 6%
⇒ Loss% =
× 100%
=
× 100%
⇒ 6 =
× 100
SP = 47
viii) Matches A
Given, CP = 50, Profit = 4
⇒ Profit = SP-CP
⇒ SP = Profit + Cp
= 4 + 50 = 54
ix) Matches F
Given, Cp = 40, SP = 50
⇒ Profit = SP-CP
= 50-40 = 10
Profit% =
× 100% =
× 100%
Profit% = 25%
x) Matches K
Given, CP = 50, SP = 60
⇒ Profit = SP-CP
= 60-50 = 10
Profit% =
× 100% =
× 100%
Profit% = 20%
xi) Matches D
Given, P = 800, R = 10%, T = 2year
⇒ I = ![]()
⇒ I = 160
xii) Matches l
Given, P = 150, R = 6%, T = 1year
Need to find out A
⇒ I = ![]()
= 9
⇒ A = P + I
= 159
Couldn't generate an explanation.
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