A tree breaks due to storm and the broken upper part of the tree makes an angle of 60° with the horizontal plane. The top of the tree meets the horizontal plane at a distance of 10 m from the root of the tree. Find the height of the tree before breaking. (√3 = 1.732)

Let AB is the Height of the Tree before broken the upper part, DE is the Height of the tree after broken.
Given, ∠DCE = 60o, DC = 10m
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ED = 10 × 1.732
ED = 17.32
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EC = 2
Total Height of the tree = EC + ED = 17.32 + 20
= 37.32
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