The shadow of a tower standing on a plane ground becomes 40 m longer when the angle of elevation of the Sun becomes 30° after reduction from 60°. Find the height of the tower.

Let Height of the tower is BC = g.
Given, ∠CAB = 30o∠CDB = 60o AD = 40.
in ∆CAB,
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……….(1)
in ∆CDB,
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……….(2)
Equation (1) – Equation(2)
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120 = 2g√3
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(Rationalization)
g = 20√3
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