On one side of a road a tower is situated and on the other side a house in situated. The angles of depression of the root of the house and base of the house from the top of the tower are respectively 45° and 60°. If the height of the house is 12 m then find the height of the tower. (√3 = 1.732)

Let Height of the House CD, Height of the Hill is AB.
Given, CD = 12, AE = 12
∠BCE = 30o
∠BDA = 600
In ∆ABD,
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AD√3 = BE + 12
………..(1)
In ∆BCE,
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EC = BE…………..(2)
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BE + 12 = BE√3
12 = BE(√3 – 1)
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BE = 6(√3 + 1)
Height of the tower = BE + AE = 6√3 + 6 + 12
= 28.39
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