Q3 of 20 Page 52

Let us prove that the point (–2, –11) is equidistant from the two points (–3, 7) and (4, 6).

We know that distance between two points (x1, y1) and (x2, y2) is given by .


Using the above distance formula,


Distance between (–2, –11) and (-3, 7)





Distance between (–2, –11) and (4, 6)





Hence proved that the point (–2, –11) is equidistant from the two points (–3, 7) and (4, 6).


More from this chapter

All 20 →
1

Let us calculate the distances of the following points from origin:

(i) (7, –24)


(ii) (3, –4)


(iii) (a + b, a – b)

 2

Let us calculate the distances between the two points given below:

(i) (5, 7) and (8, 3)


(ii) (7, 0) and (2, –12)


(iii) and (0, –2)


(iv) (3, 6) and (–2, –6)


(v) (1, –3) and (8, 3)


(vi) (5, 7) and (8, 3)

4

Let us show that the points (7, 9), (3, –7) and (–3, 3) are the vertices of a right angled triangle by calculation.

 5

Let us prove that in both of the following cases, the three points are the vertices of an isosceles triangle:

(i) (1, 4), (4, 1) and (8, 8)


(ii) (–2, –2), (2, 2) and (4, –4)