Let us show by calculation that the points (2, 1), (0, 0), (–1, 2) and (1, 3) are the angular points of a square.
We have A → (2, 1)
B → (0, 0)
C → (-1, 2)
D → (1, 3)
We know that distance between two points (x1, y1) and (x2, y2) is given by
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Using the above distance formula,
AB ![]()
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BC ![]()
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CD![]()
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DA ![]()
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Now, consider the diagonals, AC and BD.
AC ![]()
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BD ![]()
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We find that AB = BC = CD = DA with equal diagonals (AC = BD)
⇒ ABCD is a square.
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