Q7 of 20 Page 52

Let us show by calculation that the points (2, 1), (0, 0), (–1, 2) and (1, 3) are the angular points of a square.

We have A (2, 1)


B (0, 0)


C (-1, 2)


D (1, 3)


We know that distance between two points (x1, y1) and (x2, y2) is given by .


Using the above distance formula,


AB





BC





CD





DA





Now, consider the diagonals, AC and BD.


AC





BD





We find that AB = BC = CD = DA with equal diagonals (AC = BD)


ABCD is a square.


More from this chapter

All 20 →