Let us find a point on x-axis which is equidistant from the two points (3, 5) and (1, 3).
Let (x, 0) be a point on the x-axis equidistant from the two points (3, 5) and (1, 3).
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Squaring both sides
x2 – 6x + 34 = x2 – 2x + 10
4x = 24
∴ x = 6
The required point is (6, 0).
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