Q9 of 20 Page 52

Let us find a point on x-axis which is equidistant from the two points (3, 5) and (1, 3).

Let (x, 0) be a point on the x-axis equidistant from the two points (3, 5) and (1, 3).




Squaring both sides


x2 – 6x + 34 = x2 – 2x + 10


4x = 24


x = 6


The required point is (6, 0).


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