Q15 of 24 Page 157

In the trapezium ABCD, AB || DC and AB = 7 cm and DC = 5 cm. The midpoints of AD and BC are E and F respectively, the length of EF is

Since AB||DC and E and F are midpoints of AD and BC,


By using the theorem:-


The line segment joining the midpoints of two side of a triangle is parallel to the third side and equal to half of it, we get


⇒ AB||CD||EF


Also,



More from this chapter

All 24 →
14

ABCD is a squared figure. The two diagonals AC and BD intersect each other at the point O. The bisector of ∠BAC intersects BO at the point P and BC at the point Q. Let us prove that,

15

In the triangle PQR, ∠PQR = 90° and PR = 10 cm. If S is the midpoint of PR, then the length of QS is

 15

In the triangle ABC, E is the midpoint of the median AD; the extended BE intersects AC at the point F. If AC=10.5 cm, then the length of AF is

 15

In the triangle ABC, the midpoints of BC, CA and AB are D, E and F respectively; BE and DF intersect at the point X and CF and DE intersect at the point Y, the length of XY is equal to