Q15 of 24 Page 157

In the triangle ABC, E is the midpoint of the median AD; the extended BE intersects AC at the point F. If AC=10.5 cm, then the length of AF is


In Δ ADG, AE = ED and EF||DG, therefore F is mid point of AG.


Similarly, In Δ BFC, BD = DC and BF||DG, therefore G is mid point of FC.



⇒ AF = 3.5 cm

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