If sin 17° =
, let us show that sec 10° - sin73° = 
Given, ![]()
To show, ![]()
[sec θ = ![]()
⇒ ![]()
⇒ sin73° = sin(90 - 17) = cos17
⇒ ![]()
= ![]()
[sin2θ + cos2θ = 1]
= ![]()
= ![]()
= 
= 
= ![]()
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