Q13 of 31 Page 316

let us find the value of (tan 1° × tan2° × tan 3°………..tan89°)

⇒ tan1° tan2° tan3° ……tan87° tan88° tan89°


⇒ tan1° tan2° tan3° ……tan(90 - 3)° tan(90 - 2)° tan(90 - 1)°


⇒ tan1° tan2° tan3° …..cot3° cot2° cot1°


= 1


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