∠A + ∠B = 90°, let us show that 
Given, ∠A + ∠B = 90°
To show that ![]()
⇒ ![]()
⇒ tanB = tan(90 - A) = cotA
= ![]()
[cotA =
]
= ![]()
= 1 + tan2A
= sec2A
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, let us show that sec 10° - sin73° = 

