Q2 of 59 Page 32

Find the products:

(i) (5x + 8)3x


(ii) (–3pq) (–15p3q2 – q3)


(iii) (3a3 – 3b3)


(iv) –x2(x – 15).

(i) By using the distributive law

(5x +8) 3x


= 5x × 3x + 8× 3x


= 15x2 +24x


(ii) By using the distributive law


= (–3pq)(–15 p3q2) – (–3pq)(q3)


= 45p4q3 + 3pq4


(iii) By using the distributive law



=


(iv) By using the distributive law


= –x2 (x) – (–x2) (15)


= –x3 + 15x2


More from this chapter

All 59 →
4

Subtract:

(i) –2xy + 3xy2 from 8xy;


(ii) a – b – 2c from 4a + 6b – 2c.

 1

Complete the following table of products of two monomials:

 3

Simplify the following:

(i) (2xy – xy)(3xy – 5)


(ii) (3xy2 + 1)(4xy – 6xy2)


(iii) (3x2 + 2x)(2x2 + 3)


(iv) (2m3 + 3m)(5m – 1).

 1

Find the product:

(i) (a + 3)(a + 5)


(ii) (3t + 1)(3t + 4)


(iii) (a – 8)(a + 2)


(iv) (a – 6)(a – 2)