Q17 of 59 Page 162

The two adjacent sides of a rectangle are 2x2 – 5xy + 3z2 and 4xy – x2 – z.

Two adjacent sides are 2x2 – 5xy + 3z2 and 4xy – x2 – z.


Area of rectangle = (2x2 – 5xy + 3z2)× (4xy – x2 – z)


⇒ Area of rectangle = 2x2(4xy – x2 – z)-5xy(4xy – x2 – z) + 3z2(4xy – x2 – z)


⇒ Area of rectangle = 8x3y-2x4-2x2z-20x2y2 + 5x3y + 5xyz + 12xyz2-3x2z2-3z3


Perimeter of rectangle = 2× (2x2 – 5xy + 3z2 + 4xy – x2 – z)


⇒ Perimeter of rectangle = 2× (x2-xy + 3z2-z)


⇒ Perimeter of rectangle = (2x2-2xy + 6z2-2z)


More from this chapter

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15

If a = 3x – 5y, b = 6x + 3y and c = 2y – 4x, find

(i) a + b – c;


(ii) 2a–3b + 4c.

 16

The perimeter of a triangle is 15x2 – 23x + 9 and two of its sides are 5x2 + 8x – 1 and 6x2 – 9x + 4. Find the third side.

 18

The base and the altitude of a triangle are (3x – 4y) and (6x + 5y) respectively. Find its area.

 19

The sides of a rectangle are 2x + 3y and 3x + 2y. From this a square of side length x + y is removed. What is the area of the remaining region?