If a2 + b2∝ ab, let us prove that a + b ∝ a – b.
Given: a2 + b2∝ ab to prove a + b ∝ a-b
a2 + b2= 2kab
as 2k is a constant.
It can be written as:
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Apply componendo dividend,
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Square root on both sides,
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i.e a + b ∝ a-b
hence proved.
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