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13. Variation
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Q11 of 37 Page 195

If a ∝ b, b ∝ c let us show that a3b3 + b3c3 + c3a3∝ abc (a3 + b3 + c3).

Given: a ∝ b, b ∝ c

a = kb and b = mc


it can be written as:


a = kb = kmc and b = mc


To prove: a3b3 + b3c3 + c3a3∝ abc(a3 + b3 + c3)






Hence, a3b3 + b3c3 + c3a3∝ abc(a3 + b3 + c3)


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Questions · 37
13. Variation
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