If a ∝ b, b ∝ c let us show that a3b3 + b3c3 + c3a3∝ abc (a3 + b3 + c3).
Given: a ∝ b, b ∝ c
a = kb and b = mc
it can be written as:
a = kb = kmc and b = mc
To prove: a3b3 + b3c3 + c3a3∝ abc(a3 + b3 + c3)
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Hence, a3b3 + b3c3 + c3a3∝ abc(a3 + b3 + c3)
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