Let us fill in the blanks :
i. If
and
then x∝ _______
ii. If x ∝ y, xn∝ ________
iii. If x ∝ y and x ∝ z, then (y + z)∝ ________
(i) Given:
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Put the value of y in x.

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As k and m are constant.
⇒ x ∝ z
Hence, If
and
then x ∝ _z.
(ii) Given: x ∝ y
x = ky
xn = kn.yn
where kn is a constant.
Hence xn ∝ yn
Hence, If
__yn_
(iii) Given: x ∝ y and x ∝ z
x = ky and x = mz
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Hence, y + z = ?
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So, y + z ∝ x
If
and
then
__x__
Couldn't generate an explanation.
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