Q3 of 67 Page 87

Find the square of 1468 by writing this as 1465 + 3.

Using the identity (a + b)2 = a2 + b2 + 2ab


Here, 722 = (1465 + 3)2


= 14652 + 32 + 2×1465×3 ..(i)


Since 1465 terminates with 5,


14652 146 × (146 + 1)


= 146 × 147


= 21462


14652 = 2146225


Substituting 14652 in equation (i)


= 14652 + 32 + 2×1465×3


= 2146225 + 9 + 8790


= 2155024


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