The adjacent angles of a parallelogram are in the ratio 2:1. Find the measures of all the angles.
Let us assume a parallelogram ABCD,

We know that the sum of the adjacent angles in a parallelogram is 1800.
We also know that the angles at the opposite vertices are equal.
i.e., ∠A + ∠B = 1800. ...... - (1)
∠A = ∠C ...... ...... (2)
∠B = ∠D ...... ...... (3)
According to the problem, it is given that the adjacent angles are in the ratio of 2:1.
Let us assume that the adjacent angles be A and B.
Let’s take the values of ∠B = 2x and ∠A = x
From eq(1) we get,
⇒ x + 2x = 1800
⇒ 3x = 1800
⇒ ![]()
⇒ x = 600.
Now find the value of ∠A and ∠B,
⇒ ∠A = x
⇒ ∠A = 600
⇒ ∠B = 2x
⇒ ∠B = 2 × 600
⇒ ∠B = 1200
From (2) and (3) we get,
∠C = 600 and ∠D = 1200
The values of ∠A, ∠B, ∠C and ∠D is 600, 1200, 600, 1200.
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