Q7 of 28 Page 133

In a rhombus PQRS, if PQ = 3x − 7 and QR = x + 3, find PS.

Consider a Rhombus PQRS,



According to the problem, it is given that:


PQ = 3x - 7.


QR = x + 3.


We know that the lengths of sides of a rhombus are equal.


So, we can clearly say that,


PQ = QR


⇒ 3x - 7 = x + 3


⇒ 3x - x = 3 + 7


⇒ 2x = 10


⇒


⇒ x = 5 units


Now, let's find the length of each side,


⇒ PQ = 3x - 7


⇒ PQ = (3 × 5) - 7


⇒ PQ = 15 - 7


⇒ PQ = 8 units


Since all the sides of a rhombus are equal.


Length of side PS is 8units.


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