In a given square ABCD, if the area of triangle ABD is 36cm², find (i) the area of triangle BCD; (ii) the area of the square ABCD

Consider a square ABCD,

According to the problem, it is given that the area of ΔABD is 36cm².

We know that the diagonal of a square bisect into congruent triangles.

So, from the figure we can clearly say that

Area of ΔABD = Area of ΔBCD

So, Area of ΔBCD = 36cm².

From the figure, we can clearly say that,

Area of square ABCD = Area of ΔABD + Area of ΔBCD

Area of square ABCD = 36 + 36cm²

Area of square ABCD = 72cm².

The Area of ΔBCD = 36cm².

The Area of square ABCD = 72cm².