Find the 10th term of the sequence √2, √8, √18.......
Given Sequence,
√2,√8,√18,…
⇒√2, 2√2, 3√2, …
Let us find the difference of consecutive terms,
a2 – a1 = 2√2 – √2 = √2
a3 – a2 = 3√2 – 2√2 = √2
As consecutive differences of terms are same, therefore above series is an AP with
First term, a = √2
Common difference, d = √2
We know, nth term of an AP is
an = a + (n – 1)d
⇒ a10 = √2 + (10 – 1)√2
⇒ a10 = √2 + 9√2
⇒ a10 = 10√2
Couldn't generate an explanation.
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