If the zeroes of the polynomial f(x) = x3 – 12x2 + 39x + k are in A.P. Find the value of k.
We know, if p, q, and r are the roots of a cubic equation then
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For the given equation,
……[1]
……[2]
……[3]
As, roots are in AP we can let roots as (A – D), A, (A + D) [Where D is common difference]
From [1], we have
(A – D) + A + (A + D) = –12
⇒ 3A = –12
⇒ A = –4 ……[4]
From [2], we have
((A – D))A((A + D)) = –k
⇒ A(A2 – D2) = –k
⇒ 4(A2 – D2) = k
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From [3], we have
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⇒ 2A2 + A2 – D2 = 39
From [4] and [5]
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⇒ k = 28
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