The diameter of a garden roller is 1.4m and it is 2m long. how much area will it cover in 5 revolutions?
Given; radius of cylindrical roller = 0.7 m
Height of roller = 2m
no. of revolutions(n) = 5
So, area covered = no. of revolutions × curved surface area
= n × 2πrh
= ![]()
= 22 × 2 = 44 m2
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