If x¹¹ + 101 is divided by x + 1 then what remainder do we get.

Let p(x) = x¹¹ + 101 and g(x) = x + 1

By using remainder theorem put value of x + 1 = 0

x + 1 = 0

x = –1

Hence, p(– 1) will give the remainder of x¹¹ + 101 divided by x + 1

P(– 1) = x¹¹ + 101

P(– 1) = (–1)¹¹ + 101

P(– 1) = 101 – 1

P(– 1) = 100

∴ remainder is 100