Q9 of 13 Page 48

Find the value of x3 +y3 –12xy + 64 when x + y = – 4

(x + y)3 = x3 + y3 + 3xy (x + y)

Put value of x + y


(–4)3 = x3 + y3 + 3xy (–4)


–64 = x3 + y3 – 12xy


∴ x3 + y3 – 12xy + 64 = 0


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