Find the remainder when 9x3 – 3x2 + x – 5 is divided by
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Let p(x) = 9x3 – 3x2 + x – 5 and ![]()
By remainder theorem, p(x) divides g(x) completely when at the points where g(x) =0, p(x) = 0.
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Put the value of x in the equation
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= – 3
∴ remainder is –3
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