In a set of four integers the average of the two smallest integers is 102, the average of the three smallest integers is 103, the average of all four is 104. Which is the greatest of these integers?
Let the four integers be a, b, c, d (in ascending order)
Average of two smallest integers = 102
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a + b = 204 ..(i)
Average of three smallest integers = 103
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a + b +c = 309 ..(ii)
From equation (i) a + b = 204
⇒ c = 105
Average of all integers = 104
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a + b +c + d = 416
From equation (ii) a+ b +c = 309
⇒ d = 107
Since d is greatest integer
So, 107 is the greatest of these integers.
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