Q8 of 18 Page 226

If one side of a square is increased by 2 m and the other side is reduced by 2 m, a rectangle of perimeter 48 m is formed. Find the original side of the square.

Let the side of square be ‘s’ m.


Given that one side of square is increased by 2 m and other side is reduced by 2 m to form a rectangle.


Let length and breadth of the rectangle be ‘l’ m and ‘b’ m.


⇒ l = s + 2 and b = s – 2


We have perimeter of this rectangle = 48 m


We know, Perimeter of rectangle = 2 (length + breadth)


⇒ 48 = 2[(s + 2) + (s – 2)]


⇒ 48 = 2(2s)


⇒ 4s = 48



Thus, original side of square is 12 m.


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