Q9 of 18 Page 226

A wire of length 86 cm is bent in the form of a rectangle such that its length is 7 cm more than its breadth. Find the length and breadth of the rectangle so formed.

Given a wire of length 86 cm is bent into a rectangle.


⇒ Perimeter of rectangle = 86 cm


It is also given that length of the rectangle is 7 cm more than its breadth.


Let length and breadth of the rectangle be ‘l’ cm and ‘b’ cm.


⇒ l = b + 7


We know, Perimeter of rectangle = 2 (length + breadth)


⇒ 86 = 2(l + b)


⇒ 86 = 2[(b + 7) + b]


⇒ 86 = 2(2b + 7)


⇒ 4b + 14 = 86


⇒ 4b = 72



We have l = b + 7


⇒ l = 18 + 7


∴ l = 25 cm


Thus, length and breadth of rectangle are 25 cm and 18 cm.


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