In nature metal, 'A' is formed in the free state while metal 'B' is found in the form of its compound. Which of the two will be nearer to the top of the activity series of metal? Why?

Metal 'B' will be nearer to the top of the activity series of metal.

Explanation: The more reactive metals are placed on top in the activity series. Since the metal is reactive, it will easily form compounds. In the given case, it has been stated that metal 'B' exists in the form of its compound which in turn indicates that it is more reactive as compared to the metal 'A'.

Additional information:

The reactivity series is a series of metals, in which the metals are placed in order of reactivity from the highest to lowest. If any metal A, is at a higher position than a metal B, then A will replace B in the solution.