Q18 of 29 Page 1

Find: .

Using partial fraction method,



By cross–multiplying we get,


4 = A(x2 + 4) + (Bx + C)(x – 2)


⇒4 = Ax2 + 4A + Bx2 – 2Bx + Cx–2C


⇒4 = (A + B) x2 + (C–2B)x–2C + 4A


On equating, same coefficients we have,


A + B = 0, C–2B = 0 & 4A–2C = 0


On solving, we get





On integrating we get,



Hence,


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