Given, 
OR
Find the inverse of the matrix
, by using elementary row transformations.
|A| = 5(–1) + 4(1) = –1
C11 = –1 C21 = 8 C31 = –12
C12 = 0 C22 = 1 C32 = –2
C13 = 1 C23 = –10 C33 = 15



Hence, 
OR
Using, AA–1 = I
A = IA

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Hence, 
Couldn't generate an explanation.
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