Find the second order derivatives of each of the following functions:
sin (log x)
√Basic Idea: Second order derivative is nothing but derivative of derivative i.e. ![]()
√The idea of chain rule of differentiation: If f is any real-valued function which is the composition of two functions u and v, i.e. f = v(u(x)). For the sake of simplicity just assume t = u(x)
Then f = v(t). By chain rule, we can write the derivative of f w.r.t to x as:
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√Product rule of differentiation- ![]()
√Apart from these remember the derivatives of some important functions like exponential, logarithmic, trigonometric etc..
Let’s solve now:
Given, y = sin ( log x )
We have to find ![]()
As ![]()
So lets first find dy/dx and differentiate it again.
∴ ![]()
differentiating
using the chain rule,
let, t = log x and y = sin t
∵
[using chain rule]
![]()
Differentiating again with respect to x :
![]()
![]()
[ using product rule of differentiation]
![]()
![]()
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