Q9 of 28 Page 12

Draw a right triangle in which the sides (other than hypotenuse) are of lengths 2.2 cm and 2.2 cm. Then construct another triangle whose sides are 5/3 times the corresponding sides of the given triangle.

Step1: Construct a segment AB of 2.2 cm



Step2: Construct AC of 2.2 cm at 90°. Join B and C to get right-angled triangle ABC



Step3: Draw a ray at any angle from point A below AB



Step4: Take any distance in compass and keeping the needle of the compass on point A cut an arc on ray constructed in step3 and name that point X1. Keeping the distance in compass same keep the needle of the compass on point X1 and cut an arc on the same ray and mark that point as X2. Draw 5 such parts (greater of 5 and 3 in 5/3), i.e. by repeating this process mark points upto X5



Step5: Join X3 and B (3 being smaller of 5 and 3 in and not X5 because the ratio is greater than 1)



Step6: Now extend AB and draw a line parallel to X3B from X5 intersecting AB at D



Step7: Extend AC and draw a line parallel to BC from point D intersecting AC at E and ΔADE whose sides are times ΔABC is ready



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Draw a triangle ABC with side BC = 6 cm, AB = 5cm, and ∠ABC = 60°, then construct a triangle whose sides are of the corresponding sides of ABC.

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Draw triangle ABC with side BC = 4 cm, ∠B = 45°, ∠C = 30°. Then construct a triangle whose sides are times the corresponding sides ABC.