Q11 of 28 Page 12

Draw triangle ABC with side BC = 4 cm, ∠B = 45°, ∠C = 30°. Then construct a triangle whose sides are times the corresponding sides ABC.

Step1: Draw segment BC of 4 cm



Step2: using protractor draw a ray at angle 45° from point B and a ray at angle 30° from point C. mark intersection of both these rays as point A



Step3: Draw a ray at any angle below BC from B



Step4: Take any distance in compass and keeping the needle of the compass on point A cut an arc on ray constructed in step3 and name that point X1. Keeping the distance in compass same keep the needle of the compass on point X1 and cut an arc on the same ray and mark that point as X2. Draw 4 such parts (greater of 4 and 3 in 4/3), i.e. by repeating this process mark points upto X4



Step5: Join X3 and C (3 being smaller of 4 and 3 in and not X4 because the ratio is greater than 1)



Step6: Now extend BC and draw a line parallel to X3C from X4 intersecting BC at D



Step7: Draw a line parallel to AC from point D intersecting BA at E and ΔEBD whose sides are times ΔABC is ready



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